Standard Series
Is there a standard way, where the missing term in the series?
on the tastes of bank.there preaparing are a variety of fitness Question we get a series. Missing or 2, we find the lack HAV terms.and terms.i always try and hit a new test method, sometimes it walking, but some times I do not practice these problems .. So guys, if you know any way to these pboblems .. so plz solve my teelll …????
Every series has its unique style. We have many kinds of series and sequences are some of the arithmetic progression: regulation impact difference joint 3, 6, 9, 12, _, _, common difference is 21 3 = d 5. Term is a ₅ ₁ = a + (5-1) since ₅ = 3 +4 (3) ₅ = 15 a = 6 Terms a + ₆ ₁ (6-1) since ₆ = 3 +5 (3) = 18 ₆ geometric progression: the impact of regulations has a joint report of 2, 4, 8, 16, 32, _, _, 256 ratio of 2 a = a ₆ ₁ (r) ^ (6-1) ₆ a = 2 (2) = 64 ⁵ ₆ a harmonic progression: the same as the increase arithmetic, you must first mutual respect for each 1 / 2, 0.2, 0.125 _ reciprocal 2, 5, 8, _ ==> arithmetic with an already = D = 3 ₄ 2 + (4-1) (3) ₄ = 11 to the term, thus avoiding mutual ₄ we have a = 1 / 11 Fibonacci numbers: each number is the sum of the two previous numbers. 1, 1, 2, 3, 5, 8, 13, 21, … Lucas sequence: each term is the sum of the two preceding conditions 1, 3, 4, 7, 11, 18, 29, … FIGURES figured numbers triangular numbers and points on how you can get arranged in a triangular shape. 1, 3, 6, 10, … seat numbers, and that can be drawn dots arranged in a square. 1 4, 9, 16 … Gnomon: box. triangles are drawn as points on the same numbers of long legs 1, 3, 5, 7, 9, 11 … Oblong numbers: numbers that can be drawn as points and arranged rectangular shape. 2, 6, 12, 20, 30 .. Figured for compensation model is to get the concept of n = [2 + (x-2) (n-1) / 2] x is the n side Example of polygon is the term digital Given: triangular numbers 1, 3, 6, 10, _ Find the fifth time an = n [2 + (x-2) (n-1)] / ₅ 2 = 5 [2 + (3-2) (5-1)] / 2 = 15 ₅ there are several forms, but they are the ones that are useful.
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